sin and cos are smooth waves in [−1, 1]; tan and cot repeat every π with vertical asymptotes; sec and cosec never take values strictly between −1 and 1.
Dashed lines are asymptotes.Shaded: the humps above the axis.
sin and cos
Where sin x ≥ 0
sin x ≥ 0 on [2nπ, (2n + 1)π]; cos x ≥ 0 on [2nπ − π/2, 2nπ + π/2]. Both have range [−1, 1] and period 2π.
Summary
Domain, range, period, parity
tan and cot have period π; the other four 2π. cos and sec are even; sin, tan, cot and cosec are odd. tan and sec break at odd multiples of π/2, cot and cosec at multiples of π.
One table for all six.One sine wave in disguise.
Derivation
acosx+bsinx
With r=a2+b2, sin α = a/r, cos α = b/r: acosx+bsinx=rsin(x+α), so the range is [−r, r]. 3 cos x + 4 sin x ∈ [−5, 5].
Summary
Key formulas
sinx≥0⟺x∈⋃[2nπ,(2n+1)π] Transcendental functions and the six trig graphs
cosx≥0⟺x∈⋃[2nπ−2π,2nπ+2π] Transcendental functions and the six trig graphs
acosx+bsinx=a2+b2sin(x+α) Range of a cos x + b sin x
range [−a2+b2,a2+b2] Range of a cos x + b sin x
Worked examples
From the video
1. General solution of sin x = sin α.
x = nπ + (−1)ⁿα.
2. Range of 3 cos x + 4 sin x.
[−5, 5].
JEE-style question
Your turn
The range of 5 sin x − 12 cos x + 7 is:
(a)[−6, 20]
(b)[−13, 13]
(c)[−10, 24]
(d)[2, 12]
Show the answer and the traps
√(25 + 144) = 13, so 5 sin x − 12 cos x ∈ [−13, 13], and the whole thing is in [−6, 20]. Option (a).
(b) forgets the + 7. (c) uses 5 + 12 = 17 instead of √(5² + 12²).
(d) uses only the 5 sin x part: 7 ± 5.
Watch out
Common mistakes
Using |a| + |b| for the range of a cos x + b sin xIt is √(a² + b²).
Giving tan x a period of 2πtan and cot repeat every π.
Putting values between −1 and 1 in the range of sec x|sec x| ≥ 1.
Practice
Try these
1. Range of 3 sin x + 4 cos x − 2.
[−7, 3].
2. Domain of sec x + cosec x.
R − {nπ/2}.
3. General solution of cos x = 1/2.
x = 2nπ ± π/3.
4. On [0, 2π], where are sin x and cos x both ≥ 0?