Mathematics › Calculus › Relations and Functions · Part 17/20
1. Relations 2. Reflexive · Symmetric · Transitive 3. Equivalence 4. Functions 5. Composition 6. One-One & Onto 7. Bijections & Counting 8. Inverse 9. Wavy Curve 10. Domain & Range 11. Modulus 12. Trig Graphs 13. Trig Domains & Ranges 14. Inverse Trig 15. Exp & Log 16. [x], {x}, sgn 17. Even & Odd 18. Periodic 19. Functional Equations 20. Transformations
Relations and Functions · Part 17 of 20
Even and Odd Functions
Parity tells you a graph's symmetry before you draw it. Test even and odd functions, use the parity rules for sums, products and composites, split any function into even and odd parts, and extend a function evenly or oddly.
Builds on: Part 12 · Trigonometric Functions: Graphs and Ranges .
Video coming soon
Definitions
Mirror or rotate Even: f(−x) = f(x), symmetric about the y-axis (x²). Odd: f(−x) = −f(x), symmetric about the origin (x³). The domain must be symmetric about 0.
Odd and defined at 0 ⇒ f(0) = 0.
Compare f(−x) with f(x) and −f(x).
Testing
Replace x by −x x² + cos x even; x³ + sin x odd; x² + x neither; log((1 + x)/(1 − x)) odd; x² on [−1, 2] neither (domain not symmetric); 0 is both.
Decomposition
Even part + odd part f ( x ) = 2 f ( x ) + f ( − x ) + 2 f ( x ) − f ( − x ) . For eˣ the parts are (eˣ + e⁻ˣ)/2 and (eˣ − e⁻ˣ)/2.
They add back to eˣ.
Mirror for even, rotate for odd.
Extensions
From [0, a] to [−a, a] Even extension f(x) = f(−x), odd extension f(x) = −f(−x) for x in [−a, 0). For x² − x on [0, 2]: x² + x (even) and −x² − x (odd).
Summary
Key formulas
f ( x ) = 2 f ( x ) + f ( − x ) + 2 f ( x ) − f ( − x ) Even and odd functions
Worked examples
From the video
1. Classify x² + cos x, x³ + sin x, x² + x.
Even, odd, neither.
2. Even and odd extensions of x² − x from [0, 2].
x² + x and −x² − x on [−2, 0).
JEE-style question
Your turn
f(x) = x(eˣ − 1)/(eˣ + 1) is:
(a) odd
(b) even
(c) neither even nor odd
(d) both even and odd
Show the answer and the traps
(eˣ − 1)/(eˣ + 1) is odd: multiply top and bottom of g(−x) by eˣ. Times the odd x, it gives an even product. Option (b).
(a) misses that odd × odd is even. (c) gives up because eˣ itself is neither.
(d) would need f to be the zero function.
Watch out
Common mistakes
Calling a function even or odd on a non-symmetric domain Then it is neither.
Forgetting f(x) = 0 is both It is the only function that is both on a given domain.
Assuming odd × odd is odd Products follow sign rules: odd × odd is even.
Practice
Try these
1. Is log(x + √(x² + 1)) even or odd? Odd.
2. Even and odd parts of x² + 3x + 2. x² + 2 and 3x.
3. Is (2ˣ + 1)/(2ˣ − 1) even or odd? Odd.